Cevap:
Merhaba
Teşekkürler
Silinmesin diye
[tex]\sqrt{x} \beta \alpha \pi x^{2} \\ \neq \lim_{n \to \infty} a_n \lim_{n \to \infty} a_n \lim_{n \to \infty} a_n \lim_{n \to \infty} a_n \lim_{n \to \infty} a_n \left \{ {{y=2} \atop {x=2}} \right. \frac{x}{y} \sqrt[n]{x} \beta \alpha \frac{x}{y} x_{123} \leq \geq \alpha \pi \pi \neq \neq \pi[/tex]
