Cevap:
[tex]x = - 1 \: ıcın \: ( - 1 + 1).p( - 1) = {( - 1)}^{3} + a {( - 1)}^{2} + 3.( - 1) + 1 \\ 0 = - 1 + a - 3 + 1 \\ a = 3 \\ x - 1 = 0 \\ x = 1 \\ p(1 + 2) = p(3) \\ (3 + 1)p(3) = {3}^{3} + 3. {3}^{2} + 3.3 + 1 \\ 4p(3) = 64 \\ p(3) = 16[/tex]